Tuesday, 12 July 2016

Practice with Logarithm

Try to answer the question of logarithm with your own. If not sure with your answers, you may check answer at the bottom..


1. 
Which of the following statements is not correct?
A.log10 10 = 1
B.log (2 + 3) = log (2 x 3)
C.log10 1 = 0
D.log (1 + 2 + 3) = log 1 + log 2 + log 3


2. 
If log 2 = 0.3010 and log 3 = 0.4771, the value of log5 512 is:
A.2.870
B.2.967
C.3.876
D.3.912


3. 
log 8is equal to:
log 8
A.
1
8
B.
1
4
C.
1
2
D.
1
8













4. 
If log 27 = 1.431, then the value of log 9 is:
A.0.934
B.0.945
C.0.954
D.0.958


5. 
If loga+logb= log (a + b), then:
ba
A.a + b = 1
B.a - b = 1
C.a = b
D.a2 - b2 = 1

Answer the above question:

Answer #1: Option B
Explanation:
(a) Since loga a = 1, so log10 10 = 1.
(b) log (2 + 3) = log 5 and log (2 x 3) = log 6 = log 2 + log 3
      log (2 + 3)  log (2 x 3)
(c) Since loga 1 = 0, so log10 1 = 0.
(d) log (1 + 2 + 3) = log 6 = log (1 x 2 x 3) = log 1 + log 2 + log 3.
So, (b) is incorrect.


Answer #2: Option C
Explanation:

log5 512
=log 512
log 5
=log 29
log (10/2)
=9 log 2
log 10 - log 2
=(9 x 0.3010)
1 - 0.3010
=2.709
0.699
=2709
699
= 3.876

Answer #3: Option C
Explanation:
log 8=log (8)1/2=log 8=1.
log 8log 8log 82

Answer #4: Option C
Explanation:
log 27 = 1.431
 log (33 ) = 1.431
 3 log 3 = 1.431
 log 3 = 0.477
 log 9 = log(32 ) = 2 log 3 = (2 x 0.477) = 0.954.

Answer #5: Option A
Explanation:
loga+ logb= log (a + b)
ba
 log (a + b) = logaxb= log 1.
ba
So, a + b = 1.


That's all from me, you may try as many as you can to improve your knowledge.. If you still don't understand, refer to the example that I have been given :)
Wish you have Luck!

Logarithm with the Examples [Page 2]

Properties of Logarithms

One of the powerful things about Logarithms is that they can turn multiply into add.
loga( m × n ) = logam + logan
"the log of a multiplication is the sum of the logs"

Why is that true? See Footnote.

Using that property and the Laws of Exponents we get these useful properties:
loga(m × n) = logam + loganthe log of a multiplication is the sum of the logs
  
loga(m/n) = logam - loganthe log of a division is the difference of the logs
  
loga(1/n) = -loganthis just follows on from the previous "division" rule, because loga(1) = 0
  
loga(mr) = r ( logam )the log of m with an exponent r is r times the log of m
  
Remember: the base "a" is always the same!
book of logarithmsHistory: Logarithms were very useful before calculators were invented ... for example, instead of multiplying two large numbers, by using logarithms you could turn it into addition (much easier!)
And there were books full of Logarithm tables to help.
Let us have some fun using them:

Example: Simplify loga( (x2+1)4√x )

Start with: loga( (x2+1)4√x )
   
Use loga(mn) = logam + logan : loga( (x2+1)4 ) + loga( √x )
   
Use loga(mr) = r ( logam ) : 4 loga(x2+1) + loga( √x )
   
Also √x = x½ : 4 loga(x2+1) + loga( x½ )
   
Use loga(mr) = r ( logam ) again: 4 loga(x2+1) + ½ loga(x)
That is as far as we can simplify it ... we can't do anything with loga(x2+1).

Answer: 4 loga(x2+1) + ½ loga(x)
Note: there is no rule for handling loga(m+n) or loga(m−n)
We can also apply the logarithm rules "backwards" to combine logarithms:

Example: Turn this into one logarithm: loga(5) + loga(x) − loga(2)

Start with: loga(5) + loga(x) − loga(2)
   
Use loga(mn) = logam + logan : loga(5x) − loga(2)
   
Use loga(m/n) = logam − logan : loga(5x/2)

Answer: loga(5x/2)

The Natural Logarithm and Natural Exponential Functions

When the base is e ("Euler's Number" = 2.718281828459...) we get:
  • The Natural Logarithm loge(x)
    which is more commonly written ln(x)
  • The Natural Exponential Function ex
And the same idea that one can "undo" the other is still true:
ln(ex) = x
e(ln x) = x
And here are their graphs:
Natural Logarithm
 
Natural Exponential Function
natural logarithm function natural exponential function
Graph of f(x) = ln(x) 
Graph of f(x) = ex
Passes through (1,0) and (e,1)
 
Passes through (0,1) and (1,e)
They are the same curve with x-axis and y-axis flipped.
Which is another thing to show you they are inverse functions.
ln 
On a calculator the Natural Logarithm is the "ln" button.
Always try to use Natural Logarithms and the Natural Exponential Function whenever possible.

The Common Logarithm

When the base is 10 you get:
  • The Common Logarithm log10(x), which is sometimes written as log(x)
Engineers love to use it, but it is not used much in mathematics.
log 
On a calculator the Common Logarithm is the "log" button.
It is handy because it tells you how "big" the number is in decimal (how many times you need to use 10 in a multiplication).

Example: Calculate log10 100

Well, 10 × 10 = 100, so when 10 is used 2 times in a multiplication you get 100:
log10 100 = 2
Likewise log10 1,000 = 3, log10 10,000 = 4, and so on.

Example: Calculate log10 369

OK, best to use my calculator's "log" button:
log10 369 = 2.567...

Changing the Base

What if we want to change the base of a logarithm?
Easy! Just use this formula:
Log Change Base
"x goes up, a goes down"
Or another way to think of it is that logb a is like a "conversion factor" (same formula as above):
loga x = logb x / logb a
So now we can convert from any base to any other base.
Another useful property is:
loga x = 1 / logx a
See how "x" and "a" swap positions?

Example: Calculate 1 / log8 2

1 / log8 2 = log2 8
And 2 × 2 × 2 = 8, so when 2 is used 3 times in a multiplication you get 8:
1 / log8 2 = log2 8 = 3

But we use the Natural Logarithm more often, so this is worth remembering:
loga x = ln x / ln a

Example: Calculate log4 22


ln
My calculator doesn't have a "log4" button ...
... but it does have an "ln" button, so we can use that:

log4 22 = ln 22 / ln 4 = 3.09.../1.39... = 2.23 (to 2 decimal places)

What does this answer mean? It means that 4 with an exponent of 2.23 equals 22. So we can check that answer:
Check: 42.23 = 22.01 (close enough!)
Here is another example:

Example: Calculate log5 125

log5 125 = ln 125 / ln 5 = 4.83.../1.61... = 3 (exactly)

I happen to know that 5 × 5 × 5 = 125, (5 is used 3 times to get 125), so I expected an answer of 3, and it worked!

Real World Usage

Here are some uses for Logarithms in the real world:

Earthquakes

The magnitude of an earthquake is a Logarithmic scale.
The famous "Richter Scale" uses this formula:
M = log10 A + B
Where A is the amplitude (in mm) measured by the Seismograph
and is a distance correction factor
Nowadays there are more complicated formulas, but they still use a logarithmic scale.

Sound

Loudness is measured in Decibels (dB for short):
Loudness in dB = 10 log10 (p × 1012)
where p is the sound pressure.

Acidic or Alkaline

Acidity (or Alkalinity) is measured in pH:
pH = −log10 [H+]
where H+ is the molar concentration of dissolved hydrogen ions.
Note: in chemistry [ ] means molar concentration (moles per liter).

More Examples

Example: Solve 2 log8 x = log8 16

Start with: 2 log8 x = log8 16
   
Bring the "2" into the log: log8 x2 = log8 16
   
Remove the logs (they are same base): x2 = 16
   
Solve: x = −4 or +4
   
But ... but ... but ... you cannot have a log of a negative number!
So the −4 case is not defined.
Answer: 4
Check: use your calculator to see if this is the right answer ... also try the "-4" case.

Example: Solve ew = e2w+6

Start with: e−w = e2w+6
   
Apply ln to both sides: ln(e−w) = ln(e2w+6)
And ln(ew)=w: −w = 2w+6
   
Simplify: −3w = 6
Solve: w = 6/−3 = −2
   
Answer: w = 2
Check: e−(−2)= e2 and e2(−2)+6=e2

Footnote: Why does log(m × n) = log(m) + log(n) ?

To see why, we will use a^(log a (x)) and Log a (a^x):
First, make m and n into "exponents of logarithms": 
Log Producr Rule


Then use one of the Laws of Exponents
Finally undo the exponents.
It is one of those clever things we do in mathematics which can be described as "we can't do it here, so let's go over there, then do it, then come back"